Question

How do you evaluate `ln(e) - 3 ln(1/e) - ln(e^3)`?

Answer 1

If you know that "ln" is the natural logarithm, you might know that is a logarithm in base "e".

Explanation:

`ln(e) - 3ln(1/e) - ln(e^3)` = `1 - 3(-1) - 3` = 1.

Remember, the answer to a log is the power (exponent).
`ln(e) = 1` since e is to the first power.
`3ln(1/e) = 3(-1)` since e is to the -1 power.
and `ln(e^3)=3` since e is to the third power.