Question

If `18 L` of a gas at room temperature exerts a pressure of `64 kPa` on its container, what pressure will the gas exert if the container's volume changes to `24 L`?

Answer 1

`P_2 = 64 *18/24 = 3/4*64 = 48 kPa`

Explanation:

Given: Container with initial, `V_1 = 18L and P_1=64kPa`
Final `V_2= 24L`
Required: New Pressure
Solution Strategy: Straight application of Boyle's Law
`P_1V_1=P_2V_2; P_2=P_1V_1/V_2` substituting the known values
`P_2 = 64 *18/24 = 3/4*64 = 48 kPa`