A container with a volume of $25 L$ contains a gas with a temperature of $150^o K$ . If the temperature of the gas changes to $320 ^o K$ without any change in pressure, what must the container's new volume be?

Question

1647 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-02T13:23:13

$160/3L$

From Ideal Gas Equation; $PV=nRT$

Pressure, number of moles and Gas constant are all fixed.

$V=nRT/P$ or $V/T=nR/P$

As long as pressure and the amount of gas remains unchanged, the ratio of $V$ and $T$ is always the same.

$V_1/T_1=V_2/T_2$
$(25L)/(150K)=(V_2)/(320K)$
$V_2=160/3L$

A container with a volume of 25 L25 L contains a gas with a temperature of 150^o K150^o K. If the temperature of the gas changes to 320 ^o K320 ^o K without any change in pressure, what must the container's new volume be?