Question

A charge of `5 C` passes through a circuit every `4 s`. If the circuit can generate `48 W` of power, what is the circuit's resistance?

Answer 1

`30.72Omega`

Explanation:

`P=I^2R=(Q/t)^2R`

`thereforeR=(Pt^2)/Q^2=(48xx4^2)/5^2=30.72Omega`