Question

How do you divide `( i-1) / (i -2 )` in trigonometric form?

Answer 1

`C = (3-i)/3 = 1-i/3`

Explanation:

Given: `C= C_n/C_d=( -1+i)/(-2 +i )`
Required: The resultant to `C_n/C_d`
Solution Strategy: Multiply both nominator and denominator by complex conjugate of the denominator, `C_d= -2+i`.
Complex conjugate of `C_d^"*" =(-2 -i)`
Thus:
`C = (C_n@C_d^"*")/(C_d@C_d^"*")=[( -1+i)@(-2 -i)]/[(-2+i )@(-2 -i)]`
`C = (3-i)/3 = 1-i/3`