How do you find the missing side of a right triangle given a = 5, b = 10?

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Answer 1 · 2016-04-10T13:59:22

Use of Pythagora'sTheorem

#hyp^2# =#opp^2# + #adj^2#
Replace values....

#10^2# = #5^2# + #side^2#
100= 25 + #side^2#
100-25= #side^2#
75= #side^2#
side= #sqrt75#

Answer 2 · 2016-04-10T14:14:40

#5sqrt5#

Note: I am considering #aandb# are the right containing sides

Consider the diagram

enter image source here

Use Pythagoras theorem

#color(blue)(a^2+b^2=c^2#

Where,

#aand b# are the right-containing sides, and #c# is the Hypotenuse

(Hypotenuse is the longest side of a right triangle)

#rarr5^2+10^2=c^2#

#rarr25+100=c^2#

#rarr125=c^2#

Take the square root of both sides

#rarrsqrt125=sqrtc^2#

#color(green)(rArrc=sqrt125=sqrt(5*5*5)=5sqrt5#