How do you simplify #sqrt(60)#?
1 Answer
Apr 21, 2016
Explanation:
-
Find factors of 60 under the root.
#sqrt(2*2*5*3)=sqrt60# -
Rewrite it in the manner of exponential numbers.
#sqrt(2^2 *5*3)# -
Cancel exponential numbers and roots.
#2 sqrt(5*3)= 2 sqrt(15)#
Or you can write like this so it is faster:
(Find LCM, then the number that is repeated two, four, six (only even for even root)... times take in front of root.)