How do you simplify #sqrt(60)#?

1 Answer
Apr 21, 2016

#2sqrt15#

Explanation:

  1. Find factors of 60 under the root.
    #sqrt(2*2*5*3)=sqrt60#

  2. Rewrite it in the manner of exponential numbers.
    #sqrt(2^2 *5*3)#

  3. Cancel exponential numbers and roots.
    #2 sqrt(5*3)= 2 sqrt(15)#

Or you can write like this so it is faster:
(Find LCM, then the number that is repeated two, four, six (only even for even root)... times take in front of root.)

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