How do you factor #-6x^2+6x^3 #?

1 Answer
Hubert
May 3, 2016

#6x^2(x-1)#

Explanation:

First, you should try to 'pull out of the parentheses' as much as you can: in this case it's #6x^2#. So we divide each monomial by #6x^2#:
#-6x^2+6x^3=6x^2(-1+x)#,
We prefer the factors to be of the form #(x- text(something) )# so here we can just rearrange the last factor to obtain #6x^2(x-1)#.

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