How do you simplify $\sqrt{72} - \sqrt{147} - \sqrt{5} - \sqrt{8} + 3 \sqrt{48}$ $sqrt72-sqrt147 -sqrt5 -sqrt 8+3sqrt48$ ?

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How do you simplify $\sqrt{72} - \sqrt{147} - \sqrt{5} - \sqrt{8} + 3 \sqrt{48}$ $sqrt72-sqrt147 -sqrt5 -sqrt 8+3sqrt48$ ?

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Answer 1 · 2016-05-25T21:26:32

$4 \sqrt{2} + 5 \sqrt{3} - \sqrt{5}$ $4sqrt2 + 5sqrt3 - sqrt5$

Explanation:

simplify terms:
$\sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6 \sqrt{2}$ $sqrt72 = sqrt(36xx2) = sqrt36 xx sqrt2 =6sqrt2$
$\sqrt{147} = \sqrt{49 \times 3} = \sqrt{49} \times \sqrt{3} = 7 \sqrt{3}$ $sqrt147 = sqrt(49xx3) = sqrt49 xx sqrt3 = 7sqrt3$
$3 \sqrt{48} = 3 \times \sqrt{16 \times 3} = 3 \times \sqrt{16} \times \sqrt{3} = 3 \times 4 \sqrt{3} = 12 \sqrt{3}$ $3sqrt48 = 3 xx sqrt(16 xx 3) = 3 xx sqrt16 xx sqrt3 = 3 xx 4 sqrt3 = 12 sqrt3$
$\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}$ $sqrt8 = sqrt(4 xx 2) = sqrt4 xx sqrt2 = 2sqrt2$
add like terms:
$6 \sqrt{2} - 2 \sqrt{2} = 4 \sqrt{2}$ $6sqrt2 - 2sqrt2 = 4sqrt2$
$- 7 \sqrt{3} + 12 \sqrt{3} = 5 \sqrt{3}$ $-7sqrt3 + 12 sqrt3 = 5sqrt3$
combine:
$4 \sqrt{2} + 5 \sqrt{3} - \sqrt{5}$ $4sqrt2 + 5sqrt3 - sqrt5$

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How do you simplify $\sqrt{72} - \sqrt{147} - \sqrt{5} - \sqrt{8} + 3 \sqrt{48}$ $sqrt72-sqrt147 -sqrt5 -sqrt 8+3sqrt48$ ?

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How do you simplify √72−√147−√5−√8+3√48sqrt72-sqrt147 -sqrt5 -sqrt 8+3sqrt48?

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How do you simplify $\sqrt{72} - \sqrt{147} - \sqrt{5} - \sqrt{8} + 3 \sqrt{48}$ $sqrt72-sqrt147 -sqrt5 -sqrt 8+3sqrt48$ ?