How do you solve using the completing the square method y^2 + 16y = 2y2+16y=2?

1 Answer
HF
May 25, 2016

y = -8 +- sqrt66y=−8±√66

Explanation:

find the number needed to complete the square:
(b/2)^2 = (16/2)^2 = 64(b2)2=(162)2=64
add to both sides of w=equation
y^2 + 16y + 64 = 2 + 64y2+16y+64=2+64
factor and simplify
(y + 8)(y + 8) = 66 -> (y + 8)^2 = 66(y+8)(y+8)=66→(y+8)2=66
take square root of both sides
y + 8 = +- sqrt66y+8=±√66
subtract 8 from both sides
y = -8 +-sqrt66y=−8±√66

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