Question

How do you find the reverse distributive property of `t^2 - ts + 3t`?

Answer 1

`t(t-s+3)`

Explanation:

First ask yourself what number or variable is present in each term. Here we see that `t` occurs in each term. This is the variable that we can factor out of each term.

When we factor out `t` we must then ask ourselves what we must multiply `t` by to get the original problem.

What must we multiply `t` by to get `t^2`?

That would be `t`. So we start out with:

`t(t`

Then we ask ourselves what we multiply `t` by to obtain `-ts`.

That would be `-s` giving us:

`t(t-s`

Now for the last term we ask ourselves what we must multiply `t` by to obtain `3t`.

That of course would be `3` giving us our answer of:

`t(t-s+3)`