How do you write 8.5 times 10^(-7)8.5×10−7 in standard form?

1 Answer
Jim G.
Jun 1, 2016

already in standard form

Explanation:

To express a number in standard form we write it as follows:

axx10^n" where " 1≤a<10" and n is an integer"a×10n where 1≤a<10 and n is an integer

8.5xx10^-7" is in this form"8.5×10−7 is in this form

In case you are asking for the original number.

Then the color(blue)" -7" -7 from the index of the 10 , lets us know to move the decimal point 7 places to the left from where it has been placed between the 8 and 5.

rArr8.5xx10^-7=0.00000085⇒8.5×10−7=0.00000085

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