How do you use the product rule to differentiate sqrt(1+3x^2 )lnx^2?

1 Answer
Jun 15, 2016

Solution

Explanation:

Let us assume the following

u = sqrt(1+3x^2)
v = ln x^2
d(uv)= u .dv+v.du
d(uv) = sqrt(1+3x^2)\times1/x^2\times 2x + ln x^2 \times 1/(2sqrt(1+3x^2))\times6x
= (2sqrt(1+3x^2))/x+(3xlnx^2)/sqrt(1+3x^2)

On further reduction will lead to
(d(uv))/dx = (2+6x^2+3x^2ln x^2)/(xsqrt(1+3x^2))