A sample of an unknown substance has mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?
1 Answer
Jun 17, 2016
Q = m c
Rearrange to c = Q / (m
Explanation:
Q = 345.2J
m = 89.5 g
So
c = 345.2 / (89.5 x 20)
c = 0.193
