How do you condense 1/2log8v+log8n-2log4n-1/2log2j12log8v+log8n2log4n12log2j?

1 Answer
Jun 19, 2016

log(1/(n)sqrt((v)/j))log(1nvj)

Explanation:

By using log properties, you can write

log(8v)^(1/2)+log(8n)-log(4n)^2-log(2j)^(1/2)log(8v)12+log(8n)log(4n)2log(2j)12

and then, by grouping terms,

log(sqrt(color(red)8v)/sqrt(color(red)2j))+log((color(red)8canceln)/(color(red)16n^cancel2))

=log(sqrt((color(red)4v)/j))+log(1/(2n))

By using again log properties, you obtain

log(1/(cancel2n)cancel2sqrt((v)/j))

log(1/(n)sqrt((v)/j))