i ^i = ii= ? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Cesareo R. Jun 25, 2016 i^i=0.20788ii=0.20788 Explanation: Any complex number can be written as x +i y = (sqrt(x^2+y^2))e^{i phi}x+iy=(√x2+y2)eiϕ with {x,y}in RR^2 where phi = arctan(y/x) then (x +i y)^{x+iy} equiv ((sqrt(x^2+y^2))e^{i phi})^{(sqrt(x^2+y^2))e^{i phi}} making x = 0, y = 1 i^i = (e^{i pi/2})^{e^{i pi/2}} = (e^{i pi/2})^i = e^{-pi/2} = 0.20788 Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square (1+i)? What is the geometric interpretation of multiplying two complex numbers? What is the product of 3+2i and 1+7i? How do I use DeMoivre's theorem to solve z^3-1=0? How do I find the product of two imaginary numbers? How do you simplify (2+4i)(2-4i)? How do you multiply (-2-8i)(6+7i)? See all questions in Multiplication of Complex Numbers Impact of this question 2384 views around the world You can reuse this answer Creative Commons License