i ^i = ii= ?

1 Answer
Jun 25, 2016

i^i=0.20788ii=0.20788

Explanation:

Any complex number can be written as

x +i y = (sqrt(x^2+y^2))e^{i phi}x+iy=(x2+y2)eiϕ with {x,y}in RR^2

where phi = arctan(y/x)

then

(x +i y)^{x+iy} equiv ((sqrt(x^2+y^2))e^{i phi})^{(sqrt(x^2+y^2))e^{i phi}}

making x = 0, y = 1

i^i = (e^{i pi/2})^{e^{i pi/2}} = (e^{i pi/2})^i = e^{-pi/2} = 0.20788