How do you write the equation in point slope form given (8,7), (-2,-4)?

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Answer 1 · 2016-06-30T19:02:52

#y+4=11/10(x+2).# [#pt.(-2,-4) used]

#y-7=11/10(x-8).# [using #pt.(8,7)

Let the given pts. be #A(8,7), B(-2,-4).#

Then, by defn., slope of line #AB# is, by defn., #(y_B-y_A)/(x_B-x_A)= (-4-7)/(-2-8)=-11/-10=11/10.#

Pt. #B(-2,-4)# ies on Line #AB#

Hence, eqn. of line #AB,# in slope-pt. form, using pt.#B(-2,-4),# is :

#y-(-4)=11/10(x-(-2)),# i.e., #y+4=11/10(x+2).#

One can choose pt.#A(8,7)# to get the eqn. #y-7=11/10(x-8).#