How do you write the equation in point slope form given (8,7), (-2,-4)?

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How do you write the equation in point slope form given (8,7), (-2,-4)?

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Answer 1 · 2016-06-30T19:02:52

$y + 4 = \frac{11}{10} (x + 2) .$ $y+4=11/10(x+2).$ [#pt.(-2,-4) used]

$y - 7 = \frac{11}{10} (x - 8) .$ $y-7=11/10(x-8).$ [using #pt.(8,7)

Explanation:

Let the given pts. be $A (8, 7), B (- 2, - 4) .$ $A(8,7), B(-2,-4).$

Then, by defn., slope of line $A B$ $AB$ is, by defn., $\frac{y_{B} - y_{A}}{x_{B} - x_{A}} = \frac{- 4 - 7}{- 2 - 8} = - \frac{11}{- 10} = \frac{11}{10} .$ $(y_B-y_A)/(x_B-x_A)= (-4-7)/(-2-8)=-11/-10=11/10.$

Pt. $B (- 2, - 4)$ $B(-2,-4)$ ies on Line $A B$ $AB$

Hence, eqn. of line $A B,$ $AB,$ in slope-pt. form, using pt. $B (- 2, - 4),$ $B(-2,-4),$ is :

$y - (- 4) = \frac{11}{10} (x - (- 2)),$ $y-(-4)=11/10(x-(-2)),$ i.e., $y + 4 = \frac{11}{10} (x + 2) .$ $y+4=11/10(x+2).$

One can choose pt. $A (8, 7)$ $A(8,7)$ to get the eqn. $y - 7 = \frac{11}{10} (x - 8) .$ $y-7=11/10(x-8).$

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How do you write the equation in point slope form given (8,7), (-2,-4)?

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