Question #fef12

1 Answer
Alfredo T.
Jul 4, 2016

#Cr_2(SO_4)_3 • 12H_2O(s) + H_2O(l) -> 2[Cr(H_2O)_6]^"3+"(aq) + 3SO_4^"2-"(aq) #

Explanation:

Then the Cr(III) hexaaquocomplex undergoes a partial acid hydrolysis:

#[Cr(H_2O)_6]^"3+"(aq) + H_2O(l) rightleftharpoons [Cr(H_2O)_5(OH)]^"2+"(aq) + H_3O^+(aq)#

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