How do you find the domain and range of (2/3)^x – 9?

1 Answer

Domain: (-oo, +oo)
Range: (-9, +oo)

Explanation:

For the domain:
x can take any value. Therefore
Domain: (-oo, +oo)

The horizontal asymptote of the graph is y=-9, therefore it does not include the value y=9. It is the approached value of the function as x approaches +oo

Range: (-9, +oo)

Kindly see the graph for visual aid.
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God bless....I hope the explanation is useful.