How do you find the exact value of ${tan}^{- 1} (cos (π))$ $tan^-1(cos(pi))$ ?

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How do you find the exact value of ${tan}^{- 1} (cos (π))$ $tan^-1(cos(pi))$ ?

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Answer 1 · 2016-08-02T18:06:40

$- \frac{π}{4}$ $-pi/4$

Explanation:

Begin with the 'inside function'. That is $cos (π)$ $cos(pi)$

now $cos (π) = - 1$ $cos(pi)=-1$

$\Rightarrow {tan}^{- 1} (- 1) = - \frac{π}{4}$ $rArrtan^-1(-1)=-pi/4$

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How do you find the exact value of ${tan}^{- 1} (cos (π))$ $tan^-1(cos(pi))$ ?

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How do you find the exact value of ${tan}^{- 1} (cos (π))$ $tan^-1(cos(pi))$ ?