For what values of x, if any, does $f(x) = 1/((x-3)(x-2))$ have vertical asymptotes?

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Answer 1 · 2016-08-22T04:08:09

$x=3 & 2$

$f(x)$ is undefined or approaches infinity when the denominator is zero.

In this case, for a zero denominator:
Either factor $(x-3)$ or factor $(x-2)$ equals to zero.

Hence $x=3&2$ will give you vertical asymptotes.

For what values of x, if any, does f(x) = 1/((x-3)(x-2)) f(x) = 1/((x-3)(x-2)) have vertical asymptotes?