Question

How do you calculate the mass of HCI required to prepare 2.5 liters of a 0.08 molar solution of HCI?

Answer 1

Easy.

Explanation:

`2.5` `liters` of a `0.08` `molar` solution of `HCI` gives us `mol` `es` of `HCl` in the solution

`Molarity`*`Volume` = `mol` `es`

`0.08` `(mol)/cancel L` * `2.5 cancel L` = `0.2 mol` `es` `HCl`

Now you must convert `mol` `es` to `grams`

`Molar` `mass` of `HCl`
`H = 1.01 (g)/(mol)`
`Cl = 35 (g)/(mol)`

`HCl = 1+35=36(g)/(mol)`

`(0.2 cancel mol)/1` * `36 (g)/(cancel mol)` = `color (red) (7.2 g)` `HCl`