How do you simplify $(5/(4x^2)) / (8/x^3)$ ?

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Answer 1 · 2016-09-03T04:55:09

$frac{frac{5}{4x^2}}{frac{8}{x^3}} = frac{5x}{32}$

Multiply the "lowest common multiple" to both the numerator and the denominator.

A nice common multiple of $4x^2$ and $x^3$ is $4x^3$ .

So trying to multiply out

$frac{frac{5}{4x^2} * (4x^3)}{frac{8}{x^3} * (4x^3)} = frac{5x}{32}$

Answer 2 · 2016-09-03T06:54:11

$(5x)/32$

When you have a fraction over a fraction, you can make use of the following as the first step in simplifying.

$(color(red)(a)/color(blue)(b))/(color(blue)(c)/color(red)(d)) = (color(red)(axxd))/(color(blue)(bxxc))$

$(5/(4x^2))/(8/x^3) = (5xxx^3)/(4x^2xx8)" "larr" simplify"$

= $(5x)/32$

How do you simplify (5/(4x^2)) / (8/x^3)(5/(4x^2)) / (8/x^3)?