How do you solve $3 \cdot 6^{9 r} = 92.3$ $3*6^(9r)=92.3$ ?

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Answer 1 · 2016-09-25T01:58:56

$r = 0.21249$ $r=0.21249$

$3 \cdot 6^{9 r} = 92.3$ $3*6^(9r)=92.3$

divide both sides by 3:
$\Rightarrow 6^{9 r} = \frac{92.3}{3}$ $=>6^(9r)=92.3/3$
$\Rightarrow 6^{9 r} = 30.77$ $=> 6^(9r)=30.77$

take the log of both sides:
$\Rightarrow {log 6}^{9 r} = log 30.77$ $=> log6^(9r)=log30.77$
$\Rightarrow 9 r log 6 = log 30.77$ $=>9rlog6=log30.77$

divide both sides by $log 6$ $log6$
$=> 9rcancel log6/cancellog6=log30.77/log6$

$=>9r=1.91239$ (use calculator)

divide both sides by 9
$=> (cancel9r)/cancel9=1.91239/9=0.21249$

Hence, $r=0.21249$

How do you solve 3*6^(9r)=92.33⋅69r=92.33*6^(9r)=92.3?