How do you convert r=3theta - tan theta to Cartesian form?

1 Answer
Oct 2, 2016

x² + y² = (3tan^-1(y/x) - y/x)²; x > 0, y > 0
Please see the explanation for the other two equations

Explanation:

r = 3theta - tan(theta)

Substitute sqrt(x² + y²) for r:

sqrt(x² + y²) = 3theta - tan(theta)

Square both sides:

x² + y² = (3theta - tan(theta))²

Substitute y/x for tan(theta):

x² + y² = (3theta - y/x)²; x !=0

Substitute tan^-1(y/x) for theta. NOTE: We must adjust for the theta returned by the inverse tangent function based on the quadrant:

First quadrant:

x² + y² = (3tan^-1(y/x) - y/x)²; x > 0, y > 0

Second and Third quadrant:

x² + y² = (3(tan^-1(y/x) + pi) - y/x)²; x < 0

Fourth quadrant:

x² + y² = (3(tan^-1(y/x) + 2pi) - y/x)²; x > 0, y < 0