How do you calculate the following to the correct number of significant figures?

a) (1.27g)/(5.296 mL)1.27g5.296mL

b) (12.235 g)/( 1.01 L)12.235g1.01L

c) (17.3 g + 2.785 g) / (30.20 mL)17.3g+2.785g30.20mL

1 Answer
Oct 2, 2016

a)0.240g/(mL)0.240gmL

b)12.1g/L12.1gL

c)0.666g/(mL)0.666gmL

Explanation:

When dividing, the quotient should have the same number of significant figures as the smaller number of sig figs in either the dividend or divisor.

When adding, the sum should have the same number of signficant figures as the "least accurate" place in the addends.

a) (1.27g)/(5.296mL)=0.2398g/(mL)1.27g5.296mL=0.2398gmL

which I will round to 0.240 g/(mL)0.240gmL because 1.271.27 has only 3 significant figures.

b)(12.235g)/(1.01L)= (12.114g)/L12.235g1.01L=12.114gL

which I will round to 12.1g/L12.1gL because 1.011.01 has only 3 sig figs.

c)frac{17.3g+2.785g}{30.20mL}17.3g+2.785g30.20mL

First add the numbers in the numerator.

17.3+2.785=20.08517.3+2.785=20.085 which I will round to 20.120.1 because the "least accurate" place in either of the addends is the tenths place in 17.317.3

Next, complete the division.

(20.1g)/(30.20mL)=0.6656g/(mL)20.1g30.20mL=0.6656gmL

which I will round to 0.666g/(mL)0.666gmL because 20.120.1 has only 3 sig figs.

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