How do you divide #-5/(-5i)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Douglas K. · Daniel L. Oct 8, 2016 #-5/(-5i) = -i# Explanation: Multiply the given fraction by #i/i#: #-5/(-5i)(i/i) = -(5i)/(-5i²)# Use #i² = -1# #-(5i)/(-5i²) = -(5i)/5# #-5/5# reduces to -1 #-(5i)/5 = -i# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 2359 views around the world You can reuse this answer Creative Commons License