How do you solve ${log}_{5} x = \frac{1}{2}$ $log_5x=1/2$ ?

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Answer 1 · 2016-10-22T08:04:20

$x = \sqrt{5}$ $x= sqrt5$

Basic rules;

$x = y^{z} and y > 1$ $x = y^z and y > 1$

$z = {log}_{y} x$ $z = log_y x$

${log}_{5} x = \frac{1}{2}$ $log_5 x= 1/2$

$x = 5^{\frac{1}{2}}$ $x = 5^(1/2)$

$x = \sqrt{5}$ $x = sqrt 5$

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