How do you solve #log_5(5^(6n+1))=13#?

Question

1679 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-24T02:27:56

#n = 2#

#log_5 5^(6n + 1) = 13#

#log_n m^x = x log_n m#

#=> (6n + 1)log_5 5 = 13#

#log_n n = 1#

#=> 6n + 1 = 13#

#=> 6n = 12#

#=> n = 2#