How do you simplify $Sin( cos^-1 (3/5))$ ?

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Answer 1 · 2016-10-31T19:29:21

$sin(cos^-1(3/5)) = 4/5$

$sin(cos^-1(3/5)) = sqrt(1 - cos^2(cos^-1(3/5))$

$sin(cos^-1(3/5)) = sqrt(1 - (cos(cos^-1(3/5)))^2$

$sin(cos^-1(3/5)) = sqrt(1 - (3/5)^2)$

$sin(cos^-1(3/5)) = sqrt(1 - 9/25)$

$sin(cos^-1(3/5)) = sqrt(16/25)$

$sin(cos^-1(3/5)) = 4/5$

How do you simplify Sin( cos^-1 (3/5))Sin( cos^-1 (3/5))?