An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $4$ $4$ . How much force is necessary to accelerate the object horizontally at $12 \frac{m}{s^{2}}$ $12 m/s^2$ ?

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An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $4$ $4$ . How much force is necessary to accelerate the object horizontally at $12 \frac{m}{s^{2}}$ $12 m/s^2$ ?

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Answer 1 · 2016-11-05T00:43:12

Force F=64Newtons.

Explanation:

This case is taken as Motion of block on a rough fixed horizontal surface.
In this case, if the block slides or moves with an acceleration under the influence of an external force 'F', the acceleration of the block is
$a = (F - f_{k}) / m$ $a=(F-f_"k")//m$
$\Rightarrow F = m a + f_{k}$ $=> F = ma + f_"k"$
Now substituting the values we get
F = (5)(12) + 4
$:. F = 64N$

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An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $4$ $4$ . How much force is necessary to accelerate the object horizontally at $12 \frac{m}{s^{2}}$ $12 m/s^2$ ?

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Explanation:

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Explanation:

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An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $4$ $4$ . How much force is necessary to accelerate the object horizontally at $12 \frac{m}{s^{2}}$ $12 m/s^2$ ?