What is the net area between $f(x) = 2/(x+1)^2$ and the x-axis over $x in [1, 2 ]$ ?

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Answer 1 · 2016-11-07T10:45:22

$1/3$
graph{(y-2/((x+1)^2))=0 [-0.168, 4.832, -0.2, 2.41]}

$2/(x+1)^2>0, AAx!=-1$

$int_1^2 2/(x+1)^2dx=-2[1/(x+1)]_1^2=-2(1/3-1/2)=-2(-1/6)=1/3$

What is the net area between f(x) = 2/(x+1)^2 f(x) = 2/(x+1)^2 and the x-axis over x in [1, 2 ]x in [1, 2 ]?