Question

How do you convert `4sqrt3-4i` to polar form?

Answer 1

`r=8`
`theta=-pi/6`

Explanation:

`4root2(3)-i4` is a vector on the Gauss plane whose length is
`r=root2(4^2*3+4^2)=8` and the angle referred to the real positive semi axis is `arctan(-1/root2(3))=-pi/6`