Question

Question #55de4

Answer 1

Assuming you meant `log_a(a/sqrtx)-log_a(sqrtax)`

`1/2-3/2log_ax`

Explanation:

`log_a(a/sqrtx)-log_a(sqrtax)=log_a((a/sqrtx)/(sqrtax))=log_a(sqrta/(x sqrtx))=log_asqrta-log_ax^(3/2)=1/2-3/2log_ax`