How do you solve for y in #3/4y=4 7/8#? Algebra Linear Equations One-Step Equations and Inverse Operations 1 Answer Jeanmarie M. Nov 16, 2016 #y=6.5# Explanation: #3/4y=4 7/8# #3/4y=39/8# Rewrite the #4 7/8# as an improper fraction #(24y)/24=156/24# Cross multiply (#3y*8#) and set it equal to (#39*4=156#) #y=6.5# Then divide by 24 on both sides Answer link Related questions What are One-Step Equations? How do you check solutions when solving one step equations? How do you solve one step equations involving addition and subtraction? How do inverse operations help solve equations? What are some examples of inverse operations? How do you solve for x in #x + 11 = 7#? How do you solve for x in #7x = 21#? How do you solve for x in # x - \frac{5}{6} = \frac{3}{8}#? How do you solve for f in #\frac{7f}{11} = \frac{7}{11}#? How do you solve for y in #\frac{3}{4} = - \frac{1}{2} \cdot y#? See all questions in One-Step Equations and Inverse Operations Impact of this question 2184 views around the world You can reuse this answer Creative Commons License