Question

What is the percent composition of nitrogen for `Sr(NO_3)_2`?

Answer 1

13.237 %

Explanation:

The molecular weight of Sr(NO3)2 is 211.62 gm
Atomic weight of Nitrogen is 14.0067 gm
Since there is two atoms of Nitrogen in Sr(NO3)2
Therefore total Nitrogen is `14.0067*2` = 28.0134
Since 28.0134 gm Nitrogen is in 211.62 gm Sr(NO3)2
Hence what is for per 100 gm [ percent] of Sr(NO3)2

So

`28.0134*100/211.62` = 13.237

Hence Answer is 13.237 %