How do you find the slope-intercept form of the equation of a line that passes through the (-5, 3) and 2,-3)?

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Answer 1 · 2016-12-08T02:56:05

#-6x + 3 = y#

y intercept = 3

m slope = - 6x

#m=(y-b)/(x-0)#

#(y2 - y1)/(x2 - x1)# = #(-3-(+3))/(2-(-5))#

#m = -6/7#

#-6/7 = (-3-3)/(2+5) = ( y - 3)/(7x +0)#

#-6/7 * (7x) + 3 = y#

#-42/7 + 3 = y#

#-6x + 3 = y#

y intercept = 3

m slope = - 6x

graph{-6x + 3 [-10, 10, -5, 5]}