How do you write the equation of a line through point (4,2); slope = 3?

1 Answer
Mia
Dec 8, 2016

y=3x-10y=3x−10

Explanation:

The general equation of a straight line is:
" "
y-y_A= a(x-x_A)y−yA=a(x−xA)
" "
where A(x,y)" "A(x,y) is the point the straight line passes through and
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a" "a is the slope.
" "
The equation of the line is:
y-2=3(x-4)y−2=3(x−4)
" "
y=3x-12+2y=3x−12+2
" "
y=3x-10y=3x−10

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