Question

Question #8b2ee

Answer 1

The mass of one atom of iron is `(9.2741105xx10^-23)`.

Explanation:

The formula we are using is `m=M/n`. Where...
=> `m` is the mass in grams.
=> `M` is the molar mass in `g/(mol)`.
=> `n_"A"` is Avogadro's number - `6.02xx10^23`.

`m=M/n_"A"`

`=55.85/(6.02xx10^23)`

`=(9.2741105xx10^-23)`

The mass of one atom of iron is `(9.2741105xx10^-23)`.

Hope this helps :)