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Given ${csc θ}^{\circ} = \frac{\sqrt{3}}{2}$ $csctheta^circ=sqrt3/2$ and ${sec θ}^{\circ} = \frac{\sqrt{3}}{3}$ $sectheta^circ=sqrt3/3$ , how do you find $sin θ$ $sintheta$ ?

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Dec 11, 2016

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