Question

How do you evaluate `sin^-1(sin((13pi)/6))`?

Answer 1

The answer is `(13pi)/6`.

Explanation:

Suppose `sin^-1` or `arcsin` or inverse `sin` of a value `x` is `y`,
i.e. `sin^-1 x = y`.

This means that `sin y = x`.

In this case, we have to evaluate inverse `sin` of `sin((13pi)/6)`, which will be `(13pi)/6`.