Question #75d2f

1 Answer
Dwight
Dec 16, 2016

the yield is 80%, as you say.

Explanation:

You start by showing that 0.100 mol C_8H_18 should yield 0.80 mol of CO_2, becaus the equation shows the ratio between these to is 2 to 16 or 1 to 8.

0.80 mol of CO_2 would have a mass of 0.8 x 44 = 35.2 g

Because the yield was only 28.16 g, rather than 352.g, the percentage yield is

28.16/35.2 x 100 = 80% (to two digits)

Related questions
See all questions in Percent Yield
Impact of this question
2201 views around the world
You can reuse this answer
Creative Commons License