Question

How do you expand `ln(2x-1)(x+1)`?

Answer 1

`ln(2x-1)+ln(x+1)`

Explanation:

Using the `color(blue)"law of logarithns"`

`color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx+logyhArrlogxy)color(white)(2/2)|)))`
`color(white)(xxxxxxxx)" applies to logs in any base"`

`rArrln(2x-1)(x+1)=ln(2x-1)+ln(x+1)`