How do you find the equation of an ellipse with vertices (0,±8) and foci (0,±4)?

1 Answer
Dec 30, 2016

x248+y264=1

Explanation:

Find the equation of an ellipse with vertices (0,±8) and foci (0,±4).

The equation of an ellipse is (xh)2a2+(yk)2b2=1 for a horizontally oriented ellipse and (xh)2b2+(yk)2a2=1 for a vertically oriented ellipse.

(h,k) is the center and the distance c from the center to the foci is given by a2b2=c2. a is the distance from the center to the vertices and b is the distance from the center to the co-vertices.

The center of the ellipse is half way between the vertices. Thus, the center (h,k) of the ellipse is (0,0) and the ellipse is vertically oriented.

a is the distance between the center and the vertices, so a=8.
c is the distance between the center and the foci, so c=4

a2b2=c2b2=a2c2

b2=8242=6416=48

The equation is:

(x0)248+(y0)264=1 or x248+y264=1