If an object is dropped, how fast will it be moving after falling $16 m$ ?

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Answer 1 · 2017-01-12T14:59:25

The velocity is $=17.7ms^-1$

Computing in the vertical direction $darr_+$

$u=0$

$a=g=9.8$

$s=16$

$v^2=u^2+2as$

$v^2=0+2*9.8*16$

$v=sqrt(2*9.8*16)=17.7ms^-1$

Answer 2 · 2017-01-12T15:01:35

$v=(28sqrt10)/5ms^(-1)$

measuring down as positive

Considering vertical motion

initial velocity $u=0 ms^(-1)$

acceleration $g=+9.8ms^(_2)$

displacement $s=16m$

$v^2=u^2+2as$

$v^2=0+2xx9.8xx16$

$v^2=313.6$

$v=sqrt313.6=(28sqrt10)/5ms^(-1)$

If an object is dropped, how fast will it be moving after falling 16 m16 m?