How do you evaluate $tan(arctan(10))$ ?

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Answer 1 · 2017-01-25T13:06:40

$tan(arctan(10))=10$

Because $arctan(x)=tan^(-1)(x)$ , we can see that $tan(x)$ and $arctan(x)$ are inverses of each other.

Remember that $f(f^(-1)(x))=x$

In this case, replace $f$ with $tan$ and $x$ with $10$ .

Then we get

$tan(tan^(-1)(10))=tan(arctan(10))=10$

Answer 2 · 2017-01-25T13:27:57

10

$tan(arctan(10)$

$:.=tan(84.28940656)$

$:.=10$

How do you evaluate tan(arctan(10))tan(arctan(10))?