Question

Question #fae95

Answer 1

`1040g`

Explanation:

The balanced equation for the combustion of octane is:
`2C_8H_18 + 25O_2 -> 16CO_2 + 18H_2O`

Therefore,
a. Calculate the number of moles of octane:
`235g * "1mol"/"114.26g" = 2.96mol`

b. Calculate the grams of carbon dioxide:
`2.96 "mol octane" * (16 "mol CO2")/(2 "mol octane") * (44.01g CO2)/(1 mol CO2) = 1042g`

(To the appropriate number of sig figs: 1040g).