How do you integrate $int dx$ ?

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Answer 1 · 2017-03-05T12:15:47

$x + C$

$intdx = int1dx = intx^0dx$

Using the standard power rule of integration,

$intx^0dx = x^(0+1)/(0+1) + C= x + C$

Answer 2 · 2017-03-05T12:16:17

$x+C$

$int dx = int x^0 dx$

Applying the power rule:

$int dx= x^(0+1)/(0+1) +C$

$=x+C$

How do you integrate int dxint dx?