A charge of $24 C$ passes through a circuit every $12 s$ . If the circuit can generate $36 W$ of power, what is the circuit's resistance?

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Answer 1 · 2017-03-05T16:11:30

$9Omega$

Current is given by

$I = Q/t = (24C)/(12s) = 2A$

and power by

$P=IV = I^2R$ ,

so

$R = P/I^2 = 36/2^2 = 9Omega$

A charge of 24 C24 C passes through a circuit every 12 s12 s. If the circuit can generate 36 W36 W of power, what is the circuit's resistance?