Question

What is the standard form of the equation of this parabola `y^2+6y+x+10=0`?

Answer 1

$$ y = \sqrt(-x-10+9) -3 $$

Explanation:

$$ (y+3)^2 = y^2+9+6y $$
$$ y^2+6y = (y+3)^2-9 $$
$$ y^2+6y + x + 10 = (y+3)^2-9 + x + 10 = 0 $$
$$ (y+3)^2 = -x-10+9 $$
$$ y+3 = \sqrt(-x-10+9) $$
$$ y = \sqrt(-x-10+9) -3 $$